3x^2-6x-375=0

Solution for 3x^2-6x-375=0 equation:

3x^2-6x-375=0

a = 3; b = -6; c = -375;
Δ = b2-4ac
Δ = -62-4·3·(-375)
Δ = 4536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4536}=\sqrt{324*14}=\sqrt{324}*\sqrt{14}=18\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18\sqrt{14}}{2*3}=\frac{6-18\sqrt{14}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18\sqrt{14}}{2*3}=\frac{6+18\sqrt{14}}{6}
$